Arithmetic mean in real world problems worksheets, solved worksheet problems or exercises with step-by-step work, formative assessment as online test, calculator and more learning resources to learn, practice, assess and master the basic math skills of **statistics**.

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1

Find the arithmetic mean of the following data. 58, 76, 40, 35, 46, 45, 0 and 100

2

Find the arithmetic mean of first 10 natural numbers.

3

Find the arithmetic mean of natural numbers from 10 to 20.

4

Find the arithmetic mean of the following data. 5.1, 4.8, 4.3, 4.5, 5.1, 4.7, 4.5, 5.2, 5.4, 5.8, 4.3, 5.6, 5.2 and 5.5

5

Find the arithmetic mean of even numbers from 2 to 20.

6

Find the arithmetic mean of first 15 odd numbers.

7

If the mean of the following numbers is 38, find the value of x. 48, x, 37, 38, 36, 27, 35, 34, 38, 49 and 33.

8

Find the arithmetic mean of odd numbers from 4 to 15.

9

Find the arithmetic mean of first 15 prime numbers.

10

Find the arithmetic mean of first 20 even numbers.

Answers Key

Show All Workout

1

Find the arithmetic mean of the following data. 58, 76, 40, 35, 46, 45, 0 and 100

Mean is 50

Solution

Mean = Sum of all observations/Number of observations

Mean = (58+76+40+35+46+45+0+100)/ 8

Sum = 400

Mean = 400/8

∴ Mean = 502

Find the arithmetic mean of first 10 natural numbers.

Mean of first 10 natural numbers are 5.5

Solution

Mean = Sum of all observations/Number of observations

Sum of first n natural number= (n/2)x(a+T_{n})

where a= first term of natural numbers,

n= total number of natural numbers and

T_{n}= last term of natural numbers.

∴ a= 1, n= 10 and T_{n}= 10

Sum of first 10 natural numbers= (10/2)x(1+10) =55

Mean of first 10 natural numbers= 55/10

∴ Mean= 5.5

3

Find the arithmetic mean of natural numbers from 10 to 20.

Mean of natural numbers from 10 to 20 are 15

Solution

Mean = Sum of all observations/Number of observations

Sum of natural numbers from start to end= (n/2)x(a+T_{n})

where a= first term of natural numbers,

n= total number of natural numbers and

T_{n}= last term of natural numbers.

∴ a= 10, n= 11 and T_{n}= 20.

Sum of natural numbers from 10 to 20 = (11/2)x(10+20) =165

Mean of natural numbers from 10 and 20=165/11

∴ Mean= 15

4

Find the arithmetic mean of the following data. 5.1, 4.8, 4.3, 4.5, 5.1, 4.7, 4.5, 5.2, 5.4, 5.8, 4.3, 5.6, 5.2 and 5.5

Mean is 5

Solution

Mean = Sum of all observations/Number of observations

Mean = (5.1+4.8+4.3+4.5+5.1+4.7+4.5+5.2+5.4+5.8+4.3+5.6+5.2+5.5)/ 14

Sum = 70

Mean = 70/14

∴ Mean = 55

Find the arithmetic mean of even numbers from 2 to 20.

Mean of even numbers from 2 to 20 are 11

Solution

Mean = Sum of all observations/Number of observations

Sum of even numbers from start to end= (n/2)x(a+T_{n})

where a= first term of even numbers,

n= total number of even numbers and

T_{n}= last term of even numbers.

∴ a= 2, n= 10 and T_{n}= 20.

Sum of even numbers from 2 to 20 = (10/2)x(2+20) =110

Mean of even numbers from 2 and 20=110/10

∴ Mean= 11

6

Find the arithmetic mean of first 15 odd numbers.

Mean of first 15 odd numbers are 15

Solution

Mean = Sum of all observations/Number of observations

Sum of first n odd number= (n/2)x(a+T_{n})

where a= first term of odd numbers,

n= total number of odd numbers and

T_{n}= last term of odd numbers.

∴ a= 1, n= 15 and T_{n}= 29

Sum of first 15 odd numbers= (15/2)x(1+29) =225

Mean of first 15 odd numbers= 225/15

∴ Mean= 15

7

If the mean of the following numbers is 38, find the value of x. 48, x, 37, 38, 36, 27, 35, 34, 38, 49 and 33.

The value of x is 43

Solution

Mean = Sum of all observations/Number of observations

Mean = (48+x+37+38+36+27+35+34+38+49+33)/ 11

Sum = 375

Mean = 375/11

38= (375 + x)/11

(38x11) = (375 + x)

418=375 + x

∴ x = 418 - 375

Hence, the value of x = 43

8

Find the arithmetic mean of odd numbers from 4 to 15.

Mean of odd numbers from 4 to 15 are 10

Solution

Mean = Sum of all observations/Number of observations

Sum of odd numbers from start to end= (n/2)x(a+T_{n})

where a= first term of odd numbers,

n= total number of odd numbers and

T_{n}= last term of odd numbers.

∴ a= 5, n= 6 and T_{n}= 15.

Sum of odd numbers from 4 to 15 = (6/2)x(5+15) =60

Mean of odd numbers from 4 and 15=60/6

∴ Mean= 10

9

Find the arithmetic mean of first 15 prime numbers.

Mean of first 15 prime numbers are 21.8667

Solution

Mean = Sum of all observations/Number of observations

Mean = (2+3+5+7+11+13+17+19+23+29+31+37+41+43+47)/ 15

Sum = 328

Mean = 328/15

Mean of first 15 prime numbers = 21.866710

Find the arithmetic mean of first 20 even numbers.

Mean of first 20 even numbers are 21

Solution

Mean = Sum of all observations/Number of observations

Sum of first n even number= (n/2)x(a+T_{n})

where a= first term of even numbers,

n= total number of even numbers and

T_{n}= last term of even numbers.

∴ a= 2, n= 20 and T_{n}= 40

Sum of first 20 even numbers= (20/2)x(2+40) =420

Mean of first 20 even numbers= 420/20

∴ Mean= 21

Online Test

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