Area and perimeter of square, rectangle and circle worksheets, solved worksheet problems or exercises with step-by-step work, formative assessment as online test, calculator and more learning resources to learn, practice, assess and master the basic math skills of **geometry**.

Area and Perimeter of Square, Rectangle and Circle

Name
Grade
School

Date
Questions20
Score

1

Find the area of given Circle

9 in

2

Find the area of given Square

8 in8 in8 in8 in

3

Find the area of given Right Triangle

9 in8 in

4

Find the area of given Rectangle

8 in2 in8 in2 in

5

Find the area of given Right Triangle

8 in3 in

6

Find the area of given Rectangle

9 in8 in9 in8 in

7

Find the area of given Circle

8 in

8

Find the area of given Square

5 in5 in5 in5 in

9

Find the area of given Right Triangle

8 in2 in

10

Find the area of given Rectangle

4 in3 in4 in3 in

11

Find the perimeter of given Triangle

7 in7 in3 in

12

Find the perimeter of given Rectangle

8 in2 in8 in2 in

13

Find the perimeter of given Pentagon

6 in6 in6 in6 in6 in

14

Find the perimeter of given Circle

8 in

15

Find the perimeter of given Square

8 in8 in8 in8 in

16

Find the perimeter of given Circle

9 in

17

Find the perimeter of given Trapezoid

5 in10 in9 in4 in

18

Find the perimeter of given Rectangle

5 in2 in5 in2 in

19

Find the perimeter of given Parallelogram

4 in2 in4 in2 in

20

Find the perimeter of given Square

10 in10 in10 in10 in

Solved Worksheet Problems

Show All Workout

1

Find the area of given Circle

9 in

Area = 254.47 in_{2}

Solution

Area of the circle = π x r^{2}

Radius (r) = 9 in

Area = 3.14 x 9 x 9 ; where π = 3.14

Area = 254.47 in^{2}

Radius (r) = 9 in

Area = 3.14 x 9 x 9 ; where π = 3.14

Area = 254.47 in

2

Find the area of given Square

8 in8 in8 in8 in

Area = 64 in_{2}

Solution

Area of the square = side^{2}

Side = 8 in

Area = 8 x 8

Area = 64 in^{2}

Side = 8 in

Area = 8 x 8

Area = 64 in

3

Find the area of given Right Triangle

9 in8 in

Area = 36 in_{2}

SolutionBase (b) = 8 in

Height (h) = 9 inArea =36 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 9 in

Area =

12

x 8 x 9

4

Find the area of given Rectangle

8 in2 in8 in2 in

Area = 16 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 8 in

Breadth (b) = 2 in

Area = 8 x 2

Area = 16 in^{2}

Length (l) = 8 in

Breadth (b) = 2 in

Area = 8 x 2

Area = 16 in

5

Find the area of given Right Triangle

8 in3 in

Area = 12 in_{2}

SolutionBase (b) = 3 in

Height (h) = 8 inArea =12 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 8 in

Area =

12

x 3 x 8

6

Find the area of given Rectangle

9 in8 in9 in8 in

Area = 72 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 9 in

Breadth (b) = 8 in

Area = 9 x 8

Area = 72 in^{2}

Length (l) = 9 in

Breadth (b) = 8 in

Area = 9 x 8

Area = 72 in

7

Find the area of given Circle

8 in

Area = 201.06 in_{2}

Solution

Area of the circle = π x r^{2}

Radius (r) = 8 in

Area = 3.14 x 8 x 8 ; where π = 3.14

Area = 201.06 in^{2}

Radius (r) = 8 in

Area = 3.14 x 8 x 8 ; where π = 3.14

Area = 201.06 in

8

Find the area of given Square

5 in5 in5 in5 in

Area = 25 in_{2}

Solution

Area of the square = side^{2}

Side = 5 in

Area = 5 x 5

Area = 25 in^{2}

Side = 5 in

Area = 5 x 5

Area = 25 in

9

Find the area of given Right Triangle

8 in2 in

Area = 8 in_{2}

SolutionBase (b) = 2 in

Height (h) = 8 inArea =8 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 8 in

Area =

12

x 2 x 8

10

Find the area of given Rectangle

4 in3 in4 in3 in

Area = 12 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 4 in

Breadth (b) = 3 in

Area = 4 x 3

Area = 12 in^{2}

Length (l) = 4 in

Breadth (b) = 3 in

Area = 4 x 3

Area = 12 in

11

Find the perimeter of given Triangle

7 in7 in3 in

Perimeter = 17 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 7 in

side 2 = 7 in

side 3 = 3 in

Perimeter = 7 + 7 + 3

∴ Perimeter = 17 in

side 1 = 7 in

side 2 = 7 in

side 3 = 3 in

Perimeter = 7 + 7 + 3

∴ Perimeter = 17 in

12

Find the perimeter of given Rectangle

8 in2 in8 in2 in

Perimeter = 20 in

Solution

Perimeter of a Rectangle = 2(l+b)

Length (l) = 8 in

Breadth (b) = 2 in

Perimeter = 2 x (8 + 2)

∴ Perimeter = 20 in

Length (l) = 8 in

Breadth (b) = 2 in

Perimeter = 2 x (8 + 2)

∴ Perimeter = 20 in

13

Find the perimeter of given Pentagon

6 in6 in6 in6 in6 in

Perimeter = 30 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

Side = 6 in

Perimeter = 6 + 6 + 6 + 6 + 6

∴ Perimeter = 30 in

Side = 6 in

Perimeter = 6 + 6 + 6 + 6 + 6

∴ Perimeter = 30 in

14

Find the perimeter of given Circle

8 in

Perimeter = 50.27 in

Solution

Perimeter of a circle = 2 x π x r

Radius (r) = 8 in

Perimeter = 2 x 3.14 x 8 ; where π = 3.14

∴ Perimeter = 50.27 in

Radius (r) = 8 in

Perimeter = 2 x 3.14 x 8 ; where π = 3.14

∴ Perimeter = 50.27 in

15

Find the perimeter of given Square

8 in8 in8 in8 in

Perimeter = 32 in

Solution

Perimeter of a square = 4 x side

side = 8 in

Perimeter = 4 x 8

∴ Perimeter = 32 in

side = 8 in

Perimeter = 4 x 8

∴ Perimeter = 32 in

16

Find the perimeter of given Circle

9 in

Perimeter = 56.55 in

Solution

Perimeter of a circle = 2 x π x r

Radius (r) = 9 in

Perimeter = 2 x 3.14 x 9 ; where π = 3.14

∴ Perimeter = 56.55 in

Radius (r) = 9 in

Perimeter = 2 x 3.14 x 9 ; where π = 3.14

∴ Perimeter = 56.55 in

17

Find the perimeter of given Trapezoid

5 in10 in9 in4 in

Perimeter = 28 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 5 in

side 2 = 10 in

side 3 = 9 in

side 4 = 4 in

Perimeter = 5 + 10 + 9 + 4

∴ Perimeter = 28 in

side 1 = 5 in

side 2 = 10 in

side 3 = 9 in

side 4 = 4 in

Perimeter = 5 + 10 + 9 + 4

∴ Perimeter = 28 in

18

Find the perimeter of given Rectangle

5 in2 in5 in2 in

Perimeter = 14 in

Solution

Perimeter of a Rectangle = 2(l+b)

Length (l) = 5 in

Breadth (b) = 2 in

Perimeter = 2 x (5 + 2)

∴ Perimeter = 14 in

Length (l) = 5 in

Breadth (b) = 2 in

Perimeter = 2 x (5 + 2)

∴ Perimeter = 14 in

19

Find the perimeter of given Parallelogram

4 in2 in4 in2 in

Perimeter = 12 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 4 in

side 2 = 2 in

side 3 = 4 in

side 4 = 2 in

Perimeter = 4 + 2 + 4 + 2

∴ Perimeter = 12 in

side 1 = 4 in

side 2 = 2 in

side 3 = 4 in

side 4 = 2 in

Perimeter = 4 + 2 + 4 + 2

∴ Perimeter = 12 in

20

Find the perimeter of given Square

10 in10 in10 in10 in

Perimeter = 40 in

Solution

Perimeter of a square = 4 x side

side = 10 in

Perimeter = 4 x 10

∴ Perimeter = 40 in

side = 10 in

Perimeter = 4 x 10

∴ Perimeter = 40 in

Question:

Find the area of given shape.

Answer:

Find the area of given shape.

Answer:

Solution

Area of the circle = π x r^{2}

Radius (r) = 2 m

Area = 3.14 x 2 x 2 ; where π = 3.14

Area = 12.57 m²

Radius (r) = 2 m

Area = 3.14 x 2 x 2 ; where π = 3.14

Area = 12.57 m²