Area and perimeter of square, rectangle and circle worksheets, solved worksheet problems or exercises with step-by-step work, formative assessment as online test, calculator and more learning resources to learn, practice, assess and master the basic math skills of geometry.

Area and Perimeter of Square, Rectangle and Circle

Name
Grade
School

Date
Questions20
Score

1

Find the area of given Circle

9 in

2

Find the area of given Square

8 in8 in8 in8 in

3

Find the area of given Right Triangle

9 in8 in

4

Find the area of given Rectangle

8 in2 in8 in2 in

5

Find the area of given Right Triangle

8 in3 in

6

Find the area of given Rectangle

9 in8 in9 in8 in

7

Find the area of given Circle

8 in

8

Find the area of given Square

5 in5 in5 in5 in

9

Find the area of given Right Triangle

8 in2 in

10

Find the area of given Rectangle

4 in3 in4 in3 in

11

Find the perimeter of given Triangle

7 in7 in3 in

12

Find the perimeter of given Rectangle

8 in2 in8 in2 in

13

Find the perimeter of given Pentagon

6 in6 in6 in6 in6 in

14

Find the perimeter of given Circle

8 in

15

Find the perimeter of given Square

8 in8 in8 in8 in

16

Find the perimeter of given Circle

9 in

17

Find the perimeter of given Trapezoid

5 in10 in9 in4 in

18

Find the perimeter of given Rectangle

5 in2 in5 in2 in

19

Find the perimeter of given Parallelogram

4 in2 in4 in2 in

20

Find the perimeter of given Square

10 in10 in10 in10 in

Solved Worksheet Problems

Show All Workout

1

Find the area of given Circle

9 in

Area = 254.47 in_{2}

Solution

Area of the circle = π x r^{2}

Radius (r) = 9 in

Area = 3.14 x 9 x 9 ; where π = 3.14

Area = 254.47 in^{2}

Radius (r) = 9 in

Area = 3.14 x 9 x 9 ; where π = 3.14

Area = 254.47 in

2

Find the area of given Square

8 in8 in8 in8 in

Area = 64 in_{2}

Solution

Area of the square = side^{2}

Side = 8 in

Area = 8 x 8

Area = 64 in^{2}

Side = 8 in

Area = 8 x 8

Area = 64 in

3

Find the area of given Right Triangle

9 in8 in

Area = 36 in_{2}

SolutionBase (b) = 8 in

Height (h) = 9 inArea =36 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 9 in

Area =

12

x 8 x 9

4

Find the area of given Rectangle

8 in2 in8 in2 in

Area = 16 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 8 in

Breadth (b) = 2 in

Area = 8 x 2

Area = 16 in^{2}

Length (l) = 8 in

Breadth (b) = 2 in

Area = 8 x 2

Area = 16 in

5

Find the area of given Right Triangle

8 in3 in

Area = 12 in_{2}

SolutionBase (b) = 3 in

Height (h) = 8 inArea =12 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 8 in

Area =

12

x 3 x 8

6

Find the area of given Rectangle

9 in8 in9 in8 in

Area = 72 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 9 in

Breadth (b) = 8 in

Area = 9 x 8

Area = 72 in^{2}

Length (l) = 9 in

Breadth (b) = 8 in

Area = 9 x 8

Area = 72 in

7

Find the area of given Circle

8 in

Area = 201.06 in_{2}

Solution

Area of the circle = π x r^{2}

Radius (r) = 8 in

Area = 3.14 x 8 x 8 ; where π = 3.14

Area = 201.06 in^{2}

Radius (r) = 8 in

Area = 3.14 x 8 x 8 ; where π = 3.14

Area = 201.06 in

8

Find the area of given Square

5 in5 in5 in5 in

Area = 25 in_{2}

Solution

Area of the square = side^{2}

Side = 5 in

Area = 5 x 5

Area = 25 in^{2}

Side = 5 in

Area = 5 x 5

Area = 25 in

9

Find the area of given Right Triangle

8 in2 in

Area = 8 in_{2}

SolutionBase (b) = 2 in

Height (h) = 8 inArea =8 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 8 in

Area =

12

x 2 x 8

10

Find the area of given Rectangle

4 in3 in4 in3 in

Area = 12 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 4 in

Breadth (b) = 3 in

Area = 4 x 3

Area = 12 in^{2}

Length (l) = 4 in

Breadth (b) = 3 in

Area = 4 x 3

Area = 12 in

11

Find the perimeter of given Triangle

7 in7 in3 in

Perimeter = 17 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 7 in

side 2 = 7 in

side 3 = 3 in

Perimeter = 7 + 7 + 3

∴ Perimeter = 17 in

side 1 = 7 in

side 2 = 7 in

side 3 = 3 in

Perimeter = 7 + 7 + 3

∴ Perimeter = 17 in

12

Find the perimeter of given Rectangle

8 in2 in8 in2 in

Perimeter = 20 in

Solution

Perimeter of a Rectangle = 2(l+b)

Length (l) = 8 in

Breadth (b) = 2 in

Perimeter = 2 x (8 + 2)

∴ Perimeter = 20 in

Length (l) = 8 in

Breadth (b) = 2 in

Perimeter = 2 x (8 + 2)

∴ Perimeter = 20 in

13

Find the perimeter of given Pentagon

6 in6 in6 in6 in6 in

Perimeter = 30 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

Side = 6 in

Perimeter = 6 + 6 + 6 + 6 + 6

∴ Perimeter = 30 in

Side = 6 in

Perimeter = 6 + 6 + 6 + 6 + 6

∴ Perimeter = 30 in

14

Find the perimeter of given Circle

8 in

Perimeter = 50.27 in

Solution

Perimeter of a circle = 2 x π x r

Radius (r) = 8 in

Perimeter = 2 x 3.14 x 8 ; where π = 3.14

∴ Perimeter = 50.27 in

Radius (r) = 8 in

Perimeter = 2 x 3.14 x 8 ; where π = 3.14

∴ Perimeter = 50.27 in

15

Find the perimeter of given Square

8 in8 in8 in8 in

Perimeter = 32 in

Solution

Perimeter of a square = 4 x side

side = 8 in

Perimeter = 4 x 8

∴ Perimeter = 32 in

side = 8 in

Perimeter = 4 x 8

∴ Perimeter = 32 in

16

Find the perimeter of given Circle

9 in

Perimeter = 56.55 in

Solution

Perimeter of a circle = 2 x π x r

Radius (r) = 9 in

Perimeter = 2 x 3.14 x 9 ; where π = 3.14

∴ Perimeter = 56.55 in

Radius (r) = 9 in

Perimeter = 2 x 3.14 x 9 ; where π = 3.14

∴ Perimeter = 56.55 in

17

Find the perimeter of given Trapezoid

5 in10 in9 in4 in

Perimeter = 28 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 5 in

side 2 = 10 in

side 3 = 9 in

side 4 = 4 in

Perimeter = 5 + 10 + 9 + 4

∴ Perimeter = 28 in

side 1 = 5 in

side 2 = 10 in

side 3 = 9 in

side 4 = 4 in

Perimeter = 5 + 10 + 9 + 4

∴ Perimeter = 28 in

18

Find the perimeter of given Rectangle

5 in2 in5 in2 in

Perimeter = 14 in

Solution

Perimeter of a Rectangle = 2(l+b)

Length (l) = 5 in

Breadth (b) = 2 in

Perimeter = 2 x (5 + 2)

∴ Perimeter = 14 in

Length (l) = 5 in

Breadth (b) = 2 in

Perimeter = 2 x (5 + 2)

∴ Perimeter = 14 in

19

Find the perimeter of given Parallelogram

4 in2 in4 in2 in

Perimeter = 12 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 4 in

side 2 = 2 in

side 3 = 4 in

side 4 = 2 in

Perimeter = 4 + 2 + 4 + 2

∴ Perimeter = 12 in

side 1 = 4 in

side 2 = 2 in

side 3 = 4 in

side 4 = 2 in

Perimeter = 4 + 2 + 4 + 2

∴ Perimeter = 12 in

20

Find the perimeter of given Square

10 in10 in10 in10 in

Perimeter = 40 in

Solution

Perimeter of a square = 4 x side

side = 10 in

Perimeter = 4 x 10

∴ Perimeter = 40 in

side = 10 in

Perimeter = 4 x 10

∴ Perimeter = 40 in

Question:

Find the area of given shape.

Answer:

Find the area of given shape.

Answer:

Solution

Area of the circle = π x r^{2}

Radius (r) = 2 m

Area = 3.14 x 2 x 2 ; where π = 3.14

Area = 12.57 m²

Radius (r) = 2 m

Area = 3.14 x 2 x 2 ; where π = 3.14

Area = 12.57 m²

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